Aleksandre Topuria vs Santiago Luna | MMA.SOCIAL

ExploreMost takedowns landed→Control-time kings→Most title-fight losses→Division breakdown & power→ Most draws — the rarest result→ Explore the MMA Data Lab→Hot Takes — post your take→Compare any two fighters→Pick'em — call the next card→Who Has More? - the daily UFC game→Build your own tier list→Make your own top 10 - fighters or fights→Champions timeline — every reign→Title reign record book→Vote in the fan polls→Most submissions of all time→Most accurate strikers ever→Best takedown defense→The round record book→Most split decisions ever→Who is the UFC GOAT?→Most knockouts of all time→Longest losing streaks ever→ Fighters never been finished→Most robbed — split-decision losses→ The greatest comeback kings→Longest UFC careers ever→Top-rated events of all time→Play free Fantasy Pick'em→Fastest-rising fighters→Pound-for-pound rankings→ Biggest upsets in UFC history→Most wins of all time→Fastest finishes ever→Busiest fighters — most fights/year→ Most five-round wars→ELO rankings — who is really #1→ Highest fan-rated fighters→Most title fights ever→

UFC Fight Night Nov 21, 2026

Bantamweight

Aleksandre Topuria

2-0-0

Santiago Luna

2-1-0

Fight night In 48 days Saturday, Nov 21

Make your pick

1,044

Topuria ELO

1,005

Luna ELO

Comments

Loading comments...

Aleksandre Topuria vs Santiago Luna fight preview, UFC Fight Night: Prochazka vs. Stirling (Nov 21, 2026) - tale of the tape: UFC wins, finishes and reach

Share image

Fight preview card

Tale of the tape in one image. Make your pick, then share it.

Download image Open full size

When is Aleksandre Topuria vs Santiago Luna?

Aleksandre Topuria vs Santiago Luna is set for UFC Fight Night: Prochazka vs. Stirling on Saturday, November 21, 2026 at ABHA Arena, ABHA Arena, Doha Qatar.

What weight class is Aleksandre Topuria vs Santiago Luna?

It is a Bantamweight bout.

MMA.SOCIAL

Fight week, in your inbox

Fantasy reminders before picks lock, plus card breakdowns and results. No spam, unsubscribe in one click.